Home > Want To > Java Play Again Loop

Java Play Again Loop

Contents

Here a quick way to add up all the elements: list = [2,4,6,8] sum = 0 for num in list: sum = sum + num print ("The sum is: %d" % The current program always works with the most recently added user. A while loop here would come after the original input, then you can error test, and inform the user they entered an invalid number, try again. This is fine in controlled situations, but it's not a very safe practice overall.

I added an additional cout after I tested it. You can try to run it on your computer, as long as you know how to interrupt runaway processes: On most systems, Ctrl-C will interrupt the currently running program. We can use a simple if test to eliminate this bug: # Start with an empty list. Here is one way to write such a loop: found = False # initial assumption for value in values_to_check(): if is_what_im_looking_for(value): found = True break #end if #end for # ... http://stackoverflow.com/questions/19108902/java-how-to-ask-user-if-he-she-wants-to-continue-program

Java Play Again Loop

I don't know of a way to check if a user enters a character instead of a number aside from using strings, and that gets pretty complicated. I just need to test it to see if it is working. Let's say you would have omitted the ; and had these lines 1
2
3
while (num < 1 || num > 10) cout << "You entered an invalid number"; cin >> num;

How many lines of code would it take to create a game that goes on forever!? Loop ? Thank you so much for the help. Java Ask User Yes Or No Maybe once I get home I'll try it myself.

Aug 4 '12 at 8:11 add a comment| up vote 8 down vote Extract the code from main into a new function, and then call that function to pass control and Java Yes Or No Loop I get errors for: while(playAgain == 'y' || playAgain == 'Y'); I think I am embarking on stuff beyond my skill This is fun. =D Last edited on Jun 17, 2012 Jun 17, 2012 at 8:36pm UTC SGM3 (110) I just started c++ and this forum. http://stackoverflow.com/questions/40893100/adding-a-loop-to-my-program-java-netbeans Next a for loop is gone into.

After some looking/research I'm still not sure this is the answer to my problem. Do You Want To Continue In Switch Case In Java x should be the starting number, x, would be 1-20 is you did rand() % 20 + 1 Hope that makes a little more sense. If you're using Python 3, you have to use input(). You can do anything you want with the variable just as you can any other variable.

Java Yes Or No Loop

if choice == '1': print("\nHere's a bicycle. current_user = unconfirmed_users.pop() print("Confirming user %s...confirmed!" % current_user.title()) # Move the current user to the list of confirmed users. Java Play Again Loop public class DiceRoller { public static void main(String[] args) { DecimalFormat df = new DecimalFormat("#.#"); Scanner sc = new Scanner(System.in); System.out.println("Welcome to the Dice Roller! " + "Do you want to Java Repeat Program Privacy policy About Wikibooks Disclaimers Developers Cookie statement Mobile view Introduction to Python Contribute Python Essentials Programming Environment   Linux   Mac   Windows Hello World Variables, Strings, and Numbers Lists and Tuples

So you want your code to look like this. One of those, you don't know why it works, but just know it does work. As the story goes, when young Gauss was in grade school his teacher got mad at his class one day. "I'll keep the lot of you busy for a while", the asked 3 years ago viewed 36835 times active 5 months ago Linked 0 How can I get my program to start over again when the user enters a 'y'? Java Ask User If They Want To Continue

But if you need to use None as a valid item in your sequence of values, then it is easy enough to define some other unique value (e.g. This is my code: import java.util.Scanner; public class Test{ public static void main(String[] args){ Scanner input = new Scanner(System.in); int ans; System.out.println("Choose an option"); System.out.print("1: To see members\n2: To add member\n3: How to disable stack tracing feature in Mathematica 11 How to take a landscape picture with mobile phone in frame ? For Loop The for loop that is used to iterate over elements of a sequence, it is often ...

Browse other questions tagged java or ask your own question. Java Y/n This section also introduces the first way to get input from your program's users. I use do whiles instead of declaring a variable, a lot of people find them annoying, for whatever reasons.

Then it sees while a < 5: and so the computer checks to see if a < 5.

Print a statement that tells the user what games you like. What would you like to do? 3 Here's a map. See you later.\n") else: print("\nI don't understand that choice, please try again.\n") # Print a message that we are all finished. Java Play Again Yes No Need to add a loop to exit or repeat program P: 5 Nasutperaah Hi all, I have written a C ++ program and now need to add a way to make

Notice that this all came about by adding one character to our program! choice = input("\nWhat would you like to do? ") # Respond to the user's choice. Give this example a try and see for yourself how it works. print("\nWelcome to the nature center.

Lucky for us, there is a way to get our code to repeat, and that's by using loops. How do Americans refer to their non-metric system in everyday circumstances? They don't as far as I know in java. names = ['guido', 'tim', 'jesse'] # Ask the user for a name.

start is the first number that is produced. Since you don't know strings yet, I opted to show you with a character. Run fast!\n") def climb_mountain(): print("\nHere's a map. I understand one aspect then another question arises.

Learn to spot infinite loops, and make sure they don't pop up in your polished programs later on. Which one ("most of it" or "all of it") is correct in the given context? more hot questions question feed lang-java about us tour help blog chat data legal privacy policy work here advertising info developer jobs directory mobile contact us feedback Technology Life / Arts asked 3 months ago viewed 42 times active 3 months ago Related 4075Is Java “pass-by-reference” or “pass-by-value”?1230Breaking out of nested loops in Java6BitShifting with BigIntegers in Java74Changing java platform on which

When you do, just interrupt the loop and figure out the logical error you made. The function should use a while loop to keep popping the first and last numbers from the list and calculate the sum of those two numbers. print("\nUnconfirmed users:") for user in unconfirmed_users: print('- ' + user.title()) print("\nConfirmed users:") for user in confirmed_users: print('- ' + user.title()) show output hide output Confirming user Daria...confirmed! The while statement only affects the lines that are tabbed in (a.k.a.

Helpful Java Resources Java Compilers What Is Java?